I calculated this from a picture and verified with distance. Numbers are approximate, and are measures with the original N42 magnets. The new N52 magnets will give even more acceleration and launch distance!

The shutter is 1/25th of a second, and the streak that is the ball is a foot long. Interpolating shows the ball to be traveling at 25 feet/second, which is 7.62 m/s. The distance from the ball at rest until the launch point is about 7 inches, or .18 m. As we all know, velocity squared = 2*acceleration*distance, and solving for acceleration, we get acceleration=161.3 m/second squared. Gravity is 9.8 m/second squared, so we're accelerating at an average of over 16 g's!

Measuring the angle of the ball's initial trajectory, you can see that I've nailed it at 45 degrees, the optimal angle for distance. (There's also stops for higher angles.) The vertical velocity is calculated as sin(45) * velocity, or about 5.4 m/s. Since t=2v/a, we substitute to get t=2*5.4/9.8=1.1 seconds in the air.

We can calculate the total distance from the horizontal velocity as cos(45) * velocity, or again, about 5.4 m/s, or 17.7 feet/second. Since d=v*t, we substitute to get d=17.7*1.1, or 19.47 feet. We've been getting about 20 feet in our tests so we can see our calculations are correct.